A capacitor having a capacitance of `100muF` is charged to a potential difference of `24V` . The charging battery is disconnected and the capacitor is connected to another battery of emf `12V` with the positive plate of the capacitor joined with the positive terminal of the battery . (a ) Find the charges on the capacitor before and after the reconnection . (b ) Find the charge flown through the 12V battery . (c ) Is work done by the battery or is it done on the battery ? find its magnitude . (d ) Find the decrease is electrostatic field energy . (e ) Find the best developed during the flow of charge after re-connection.

Options

A. `-600muC`
B. `-1200muC`
C. `600muC`
D. `1800muC`

Answer

B

Explanation

The initial charge on the capacitor `q_(i)=CV=100xx24=2400muC`. The flow of charge in the process `Deltaq=q_(f)-q_(i)=1200-2400=-1200muC`.