In the given circuit, the change on `4muF` capacitor will be:

Options

A. `13.4muC`
B. `9.6muC`
C. `5.4muC`
D. `2.4muC`

Answer

D

Explanation

`V_(A)=V_(B)=10V`
In series, potential difference across `C_(1)` is `(C_(2)V)/(C_(1)+C_(2))`
`implies`Potential difference across `4muF=(6)/(4+6)xx10=6V`
`implies`Charge`=4xx6=24muC`