What is the magnitude of the magnetic force per unit length on a wire carrying a current of 8 A making an angle of `30^@` with the direction of a uniform magnetic field of `0*15T`?

Explanation

Current in the wire `I=8A`
Magnitude of the uniform magnetic fiedl `B=0.15T`
Angle between the wire and magnetic field `theta=30^(@)`
Magnetic force per unit length on the wire is given as
`f=B I sin theta , =0.15xx8xx1xxsin 30^(@), =0.6Nm^(-3)`
Hence, the magnetic force per unit length on the wire is `0.6Nm^(-1)`