A current of `50 A` is placed through a straight wire of length `6 cm` then the magnetic induction at a point `5cm` from the either end of the wire is (`1gauss=10^-4T`)

Options

A. 2.5 gauss
B. 1.25 gauss
C. 1.5 gauss
D. 3.0 gauss

Answer

C

Explanation

`B=(mu_(0))/(4pi) i/r(sin 37^(@)+sin 37^(@))=(10^(-7)xx50)/(4xx10^(-2))xx2xx3/5=1.5xx10^(-4)T=1.5` gauss