A particle with charge `+Q` and mass m enters a magnetic field to magnitude `B` existing only of the right of the boundary `YZ` The direction of the motion of the particle is perpendicular to the direction of `B` Let `T =2pi(m)/(QB)` The time spent by the particle in the field will be
.

Options

A. `T theta`
B. `2 T theta`
C. `T((pi+2theta)/(2pi))`
D. `T((pi-2 theta)/(2pi))`

Answer

C

Explanation

`T=(2pim)/(qB), w=(2pi)/T`

Time interval for which, it will remain in region `t=((pi+2theta))/(2pi)T`