Same current `i=2A` is flowing in a wire frame as shown in figure. The frame is a combination of two equilateral triangles ACD and CDE of side 1m. It is placed in uniform magnetic field `B=4T` acting perpendicular to the plane of frame. The magnitude of magnetic force acting on the frame is

Options

A. 24N
B. zero
C. 16N
D. 8N

Answer

A

Explanation

`F_(CAD)=F_(CD)=F_(CED):.` net force on the frame `=3F_(CD)=(3)(2)(1)(4)=24N(F=ilB)`