Figure shows a square current carrying loop ABCD of side 10 cm and current i = 10A. The magnetic moment of the loop is:

Options

A. `(0.05)(hati-sqrt(3)hatk)A-m^(2)`
B. `(0.05)(hatj+hatk)A-m^(2)`
C. `(0.05)(sqrt(3)hati+hatk)A-m^(2)`
D. `(hati+hatk)A-m^(2)`

Answer

A

Explanation

Magnetic moment `(vecM)=ivecA`
`vecA`has magnitude equal to area of loop and direction is perpendicular to the plane of loop.
`vecA=(10^(-2))(cos 60 hati-sin 60 hatk)=(10^(-2))/2(hati-sqrt(3)hatk), vecM=(10)((10^(-2)))/2(hati-sqrt(3)hatk)=0.05(hati-sqrt(3)hatk)A-m^(2)`