A circular current carrying loop of radius `R=sqrt(3)cm` hangs in equilibrium in the vertical plane as shown. The loop carries a current `I=2A` in the anticlockwise direction. A horizontally directed uniform magnetic field of intensity `B=1T` exists in the region below the horizontal line AC as shown. The mass of the loop `m=` _______ gm. [Take `g=10m//s^(2)`]

Answer

6

Explanation

Force on loop due to field
= Force on major arc PQ
= BI (PQ)
`=Bl(2Rsin 60^(@))impliesF=sqrt(3)BIR` [directed vertically upwards[
Now F=mg `impliesm=(sqrt(3)BIR)/g=6 gm`