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Figure shows a coil of single turn wound...

Figure shows a coil of single turn wound on a sphere of radius R and mass m. The plane of the coil is parallel to the plane and lies in the equatorial plane of the sphere. What is the value of B if the sphere is in equilibrium when current in the coil is I?

A

`(m g cos theta)/(pi iR)`

B

`(mg)/(pi iR)`

C

`(m g tan theta)/(pi i R)`

D

`(m g sin theta)/(pi i R)`

Text Solution

Verified by Experts

The correct Answer is:
B

The gravitational torque must be counter balanced by magnetic torque about O. for equilibrium of the sphere. The gravitational torque
`impliesT_(m)=piR^(2)iB sin theta`……….1
`T_(mg)=mgR sin thetaimpliespiR^(2)iB sin theta =m gr sin theta,B=(mg)/(pi ir)`
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