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Two long conductors, separated by a dist...

Two long conductors, separated by a distance `d` carry current `I_(1) and I_(2)` in the same direction . They exert a force `F` on each other. Now the current in one of them is increased to two times and its direction is reversed . The distance is also increased to `3d`. The new value of the force between them is

A

`-2F`

B

`F/3`

C

`-(2F)/3`

D

`-F/3`

Text Solution

Verified by Experts

The correct Answer is:
C
Force acting between two current carrying conductors
`F=(mu_(0))/(2pi)(I_(1)I_(2))/d 1`………..i
Where d= distance between the conductors, l= length of small conductor
Again `F'=(mu_(0))/(2pi)((-2I_(1))(I_(2)))/((3d)) . I=_(mu_(0))/(2pi) (2I_(1)I_(2))/(3d)` .1.............ii
Thus, from eqs i and ii we have `(F')/F=-2/3impliesF'=-2/3F`
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