Find the magnetic field at point P due to a straight -line segment AB of length 6 cm carrying a current of 5A. (see figure) `(mu_(0)=4pixx10^(-7)N-A^(-2))`

Options

A. `3.0xx10^(-5)T`
B. `2.5xx10^(-5)T`
C. `2.0xx10^(-5)T`
D. `1.5xx10^(-5)T`

Answer

D

Explanation

`B=(mu_(0)I)/(4pir)(sin alpha+sinbeta)`
`r=4cm`
`sin alpha=sin beta=3//5impliesbeta=1.5xx10^(-5)T`