A particle of charge `q` and mass `m` moves in a circular orbit of radius `r` with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

Options

A. `omega` and q
B. `omega, q` and m
C. q and m
D. `omega` and m

Answer

C

Explanation

Ratio of magnetic moment and angular momentum is given by `M/L=q/(2m)`
When is a function of q and M only. This can be derived as follows `M=iA=(q.f).(pir^(2))`
`=(q)((omega)/(2pi))(pir^(2))=(qomega^(2))/2` and `L=Iomega=(m r^(2) omega):. M/L =(q(omegar^(2))/2)/(mr^(2)omega)=q/(2m)`