A proton and an `alpha`-particle, accelerated through same potential difference, enter a region of uniform magnetic field with their velocities perpendicular to the field. Compare the radii of circular paths followed by them.

Answer

`1//sqrt(2)`

Explanation

`r=(sqrt(2qVm))/(Bq)` or `r prop sqrt(m/q), (r_(p))/(r_(alpha))=sqrt((m_(P))/(m_(alpha)))sqrt((q_(alpha))/(q_(P)))=sqrt(1/4)sqrt(2/1)=1/(sqrt(2))`