In a hydrogen atom , the electron moves in an orbit of radius ` 0.5 A` making `10^( 16 ) revolutions per second . The magnetic moment associtated with the orbital motion of the electron is ……

Answer

`1.26xx10^(-23)Am^(2)`

Explanation

`1.26xx10^(-23)Am^(2)`
Equivalent current `i=qf` and magnetic moment `m=(i pir^(2))=piqfr^(2)`
Substituting the values we have `, M=(pi)(0.5xx10^(-10))^(2)(10^(16))(1.6xx10^(-19))=1.26xx10^(-23)A-m^(2)`