In the binomial expansion of `(a - b)^(n) , n ge 5` , the sum of
the ` 5^(th) and 6^(th)` terms is zero. Then, `a//b` equals

Options

A. `(n-5)/(6)`
B. `(n-4)/(5)`
C. `(5)/(n-4)`
D. `(6)/(n-5)`

Answer

B