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sum(i=0)^nsum(j=0)^m .^nCi *^iCj is equa...

`sum_(i=0)^nsum_(j=0)^m .^nC_i *^iC_j` is equal to

A

`n*2^(2n-1)`

B

`(n+1)*2^(n-1)`

C

`(n+1)*2^(n)`

D

`n*2^(n)`

Text Solution

Verified by Experts

The correct Answer is:
A
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