If sum(r=0)^25 {.^50Cr*^(50-r)C(25-r)}=K...

If `sum_(r=0)^25 {.^50C_r*^(50-r)C_(25-r)}=K(.^50C_25),` then `K` is equal to

A

`2^(24)`

B

`2^(25)-1`

C

`2^(25)`

D

`(25)^(2)`

Verified by Experts

The correct Answer is:

C

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