If an=sum(r=0)^n1/(nCr), then sum(r=0)^n...

If `a_n=sum_(r=0)^n1/(nC_r),` then `sum_(r=0)^n r/(nC_r)` equals

A

`(n-1)a_(n)`

B

`na_(n)`

C

`1/2na_(n)`

D

None of these

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Verified by Experts

The correct Answer is:

C

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