Statement 1: Lines `3x+4y+6=0,sqrt(2)x+sqrt(3)y+2sqrt(2)=0` and `4x+7y+8=0` are concurrent.
Statement 2 : If three lines are concurrent then determinant of coefficients should be non-zero.

Options

A. Statement-1 is True, Statement-2 is True and Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True and Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To determine whether the given lines are concurrent, we need to analyze the equations of the lines and check if they intersect at a common point.

### Step-by-Step Solution:

1. **Identify the equations of the lines:**
- Line 1: \(3x + 4y + 6 = 0\)
- Line 2: \(\sqrt{2}x + \sqrt{3}y + 2\sqrt{2} = 0\)
- Line 3: \(4x + 7y + 8 = 0\)

2. **Convert the equations into standard form:**
- Line 1: \(3x + 4y = -6\)
- Line 2: \(\sqrt{2}x + \sqrt{3}y = -2\sqrt{2}\)
- Line 3: \(4x + 7y = -8\)

3. **Set up the system of equations:**
We will solve the first and the third equations to find the point of intersection (let's denote the point as \((a, b)\)):
- Equation 1: \(3a + 4b + 6 = 0\) (1)
- Equation 3: \(4a + 7b + 8 = 0\) (2)

4. **Multiply the equations to eliminate \(b\):**
- Multiply equation (1) by 7:
\[ 21a + 28b + 42 = 0 \quad \text{(3)} \]
- Multiply equation (2) by 4:
\[ 16a + 28b + 32 = 0 \quad \text{(4)} \]

5. **Subtract equation (4) from equation (3):**
\[ (21a + 28b + 42) - (16a + 28b + 32) = 0 \]
This simplifies to:
\[ 5a + 10 = 0 \]
Thus,
\[ 5a = -10 \implies a = -2 \]

6. **Substitute \(a = -2\) back into one of the original equations to find \(b\):**
Using equation (1):
\[ 3(-2) + 4b + 6 = 0 \]
Simplifying gives:
\[ -6 + 4b + 6 = 0 \implies 4b = 0 \implies b = 0 \]
Therefore, the point of intersection is \((-2, 0)\).

7. **Check if this point satisfies the second line:**
Substitute \(a = -2\) and \(b = 0\) into the second line:
\[ \sqrt{2}(-2) + \sqrt{3}(0) + 2\sqrt{2} = 0 \]
This simplifies to:
\[ -2\sqrt{2} + 2\sqrt{2} = 0 \]
This is true, confirming that all three lines intersect at the point \((-2, 0)\).

8. **Conclusion for Statement 1:**
Since all three lines intersect at the same point, Statement 1 is **True**.

9. **Check Statement 2:**
Statement 2 states that if three lines are concurrent, then the determinant of their coefficients should be non-zero. We will calculate the determinant of the coefficients:
\[ \begin{vmatrix} 3 & 4 & 6 \\ \sqrt{2} & \sqrt{3} & 2\sqrt{2} \\ 4 & 7 & 8 \end{vmatrix} \]

10. **Calculate the determinant:**
Using the determinant formula:
\[ D = 3 \begin{vmatrix} \sqrt{3} & 2\sqrt{2} \\ 7 & 8 \end{vmatrix} - 4 \begin{vmatrix} \sqrt{2} & 2\sqrt{2} \\ 4 & 8 \end{vmatrix} + 6 \begin{vmatrix} \sqrt{2} & \sqrt{3} \\ 4 & 7 \end{vmatrix} \]

After calculating the determinants of the 2x2 matrices, we find that the overall determinant \(D = 0\).

11. **Conclusion for Statement 2:**
Since the determinant is zero, Statement 2 is **False**.

### Final Answer:
- Statement 1 is **True**.
- Statement 2 is **False**.