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Let A=(a,b) and B=(c,d) where c gt a g...

Let `A=(a,b)` and `B=(c,d)` where `c gt a gt 0` and `d gt b gt 0`. Then, point C on the X-axis such that `AC + BC` is the minimum, is:

A

`(bc-ad)/(b-d)`

B

`(ac+bd)/(b+d)`

C

`(ac-bd)/(b-a)`

D

`(ad+bc)/(b+d)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the point \( C \) on the X-axis such that the sum of distances \( AC + BC \) is minimized, we can follow these steps: ### Step 1: Understand the Geometry We have two points \( A = (a, b) \) and \( B = (c, d) \) where \( c > a > 0 \) and \( d > b > 0 \). The point \( C \) lies on the X-axis, which means its coordinates can be represented as \( C = (x, 0) \). ### Step 2: Write the Distance Formulas The distances from \( A \) to \( C \) and from \( B \) to \( C \) can be expressed as: - Distance \( AC = \sqrt{(x - a)^2 + (0 - b)^2} = \sqrt{(x - a)^2 + b^2} \) - Distance \( BC = \sqrt{(x - c)^2 + (0 - d)^2} = \sqrt{(x - c)^2 + d^2} \) ### Step 3: Set Up the Objective Function We want to minimize the total distance: \[ D = AC + BC = \sqrt{(x - a)^2 + b^2} + \sqrt{(x - c)^2 + d^2} \] ### Step 4: Use the Reflection Method To minimize \( D \), we can reflect point \( B \) across the X-axis to get point \( B' = (c, -d) \). The minimum distance \( AC + BC \) is equivalent to the straight line distance \( AB' \). ### Step 5: Find the Equation of the Line The coordinates of points \( A \) and \( B' \) are \( A = (a, b) \) and \( B' = (c, -d) \). The slope of line \( AB' \) is given by: \[ \text{slope} = \frac{-d - b}{c - a} \] The equation of the line can be written in point-slope form: \[ y - b = \frac{-d - b}{c - a}(x - a) \] ### Step 6: Find the Intersection with the X-axis To find the point \( C \) on the X-axis, set \( y = 0 \) in the line equation: \[ 0 - b = \frac{-d - b}{c - a}(x - a) \] Solving for \( x \): \[ -b(c - a) = (-d - b)(x - a) \] \[ -b(c - a) = -dx + da - bx + ba \] \[ (b + d)x = da + b(c - a) \] \[ x = \frac{da + b(c - a)}{b + d} \] ### Step 7: Conclusion Thus, the coordinates of point \( C \) that minimizes \( AC + BC \) are: \[ C = \left( \frac{da + b(c - a)}{b + d}, 0 \right) \]
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