Let the two foci of an ellipse be (-1, 0...

Let the two foci of an ellipse be `(-1, 0) and (3, 4)` and the foot of perpendicular from the focus `(3, 4)` upon a tangent to the ellipse be `(4, 6)`. The foot of perpendicular from the focus `(-1, 0)` upon the same tangent to the ellipse is

A

`((12)/(5),(34)/(5))`

B

`((7)/(3),(11)/(3))`

C

`(2,(17)/(4))`

D

`(-1,2)`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

Find the foot of the perpendicular from the point (2,4) upon x+y=1

Product of perpendiculars drawn from the foci upon any tangent to the ellipse 3x^(2)+4y^(2)=12 is

The foot of the perpendicular from the point P(1,3,4) to the plane 2x-y+z+3=0 is

The locus of the foot of the perpendicular drawn from the centre on any tangent to the ellipse x^2/25+y^2/16=1 is:

The feet of the perpendicular drawn from focus upon any tangent to the parabola,y=x^(2)-2x-3 lies on