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The vertices of a hyperbola are at (0, 0...

The vertices of a hyperbola are at (0, 0) and (10, 0) and one of its foci is at (18, 0). The equation of the hyperbola is

A

`(x^2)/(25)-(y^2)/(144)=1`

B

`((x-5)^2)/(25)-(y^2)/(144)=1`

C

`(x^2)/(5)-((y-5)^2)/(144)=1`

D

`((x-5)^2)/(25)-((y-5)^2)/(144)=1`

Text Solution

Verified by Experts

The correct Answer is:
B
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