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Two straight lines are perpendicular to each other. One of them touches the parabola `y^2=4a(x+a)` and the other touches `y^2=4b(x+b)` . Their point of intersection lies on the line. `x-a+b=0` (b) `x+a-b=0` `x+a+b=0` (d) `x-a-b=0`

A

`(a-x)(x+b)-ay=0`

B

`(a+x)(x-b)-ab=((a+x)(x-b))^2`

C

`(a+x)(b-x)-ay=ab`

D

`(a+x)(x-b)-ab={ab-(a+x)(x-b)}^2`

Text Solution

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The correct Answer is:
D
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