Evaluate int(0)^(2pi){cos(x)cos(2x)cos(2...

Evaluate `int_(0)^(2pi){cos(x)cos(2x)cos(2^(2)x)…cos(2^(n-1)x)cos(2^(n)-1)x}dx`.

Verified by Experts

The correct Answer is:

`pi//2^(n-1)`

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