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The degree of the differential equation ...

The degree of the differential equation of all tangent lines to the parabola `y^2 = 4ax` is

A

1

B

2

C

3

D

none of these

Text Solution

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The correct Answer is:
To find the degree of the differential equation of all tangent lines to the parabola \( y^2 = 4ax \), we can follow these steps: ### Step 1: Write the equation of the parabola The given parabola is: \[ y^2 = 4ax \] ### Step 2: Write the equation of the tangent line The equation of the tangent line to the parabola can be expressed as: \[ y = mx + \frac{a}{m} \] where \( m \) is the slope of the tangent line. ### Step 3: Differentiate the tangent line equation To find the slope \( \frac{dy}{dx} \), we differentiate the equation of the tangent line: \[ \frac{dy}{dx} = m \] ### Step 4: Substitute \( m \) in terms of \( \frac{dy}{dx} \) From the tangent line equation, we can express \( m \) as: \[ m = \frac{dy}{dx} \] Substituting this into the tangent line equation gives: \[ y = \frac{dy}{dx}x + \frac{a}{\frac{dy}{dx}} \] ### Step 5: Rearrange the equation Rearranging the equation, we get: \[ y - \frac{dy}{dx}x - \frac{a}{\frac{dy}{dx}} = 0 \] Multiplying through by \( \frac{dy}{dx} \) to eliminate the fraction: \[ y \cdot \frac{dy}{dx} - \left(\frac{dy}{dx}\right)^2 x - a = 0 \] ### Step 6: Rearranging into standard form Rearranging gives us: \[ \left(\frac{dy}{dx}\right)^2 x - y \cdot \frac{dy}{dx} + a = 0 \] ### Step 7: Divide by \( x \) Dividing the entire equation by \( x \) (assuming \( x \neq 0 \)): \[ \left(\frac{dy}{dx}\right)^2 - \frac{y}{x} \cdot \frac{dy}{dx} + \frac{a}{x} = 0 \] ### Step 8: Identify the order and degree In this equation, the highest derivative is \( \left(\frac{dy}{dx}\right)^2 \), which indicates that the order of the differential equation is 1 (since we have only the first derivative). The degree of the differential equation is determined by the highest power of the highest derivative, which in this case is 2. ### Conclusion Thus, the degree of the differential equation of all tangent lines to the parabola \( y^2 = 4ax \) is: \[ \text{Degree} = 2 \]
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