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The solution of y' =2 +2 x + 2y^2 +2 x...

The solution of ` y' =2 +2 x + 2y^2 +2 xy ^2 , y (0) =0` is :

A

`y ^2 exp .( x + ( x^2)/(2))-1`

B

`y^2=1+ c exp (x +(x^2)/(2))`

C

`y = tan ( c + x + x^2)`

D

` y=2 tan ( x +(x^2)/(2))`

Text Solution

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The correct Answer is:
D
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