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The general solution of a differential e...

The general solution of a differential equation is `y= ae ^(bx+ c) ` where are arbitrary constants. The order the differential equation is :

A

3

B

2

C

1

D

none of these

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The correct Answer is:
To determine the order of the differential equation given the general solution \( y = ae^{bx+c} \), we will follow these steps: ### Step 1: Identify the general solution The general solution of the differential equation is given as: \[ y = ae^{bx+c} \] where \( a \) and \( b \) are arbitrary constants. ### Step 2: Differentiate the equation We will differentiate \( y \) with respect to \( x \) to find the first derivative \( \frac{dy}{dx} \): \[ \frac{dy}{dx} = \frac{d}{dx}(ae^{bx+c}) = a \cdot e^{bx+c} \cdot \frac{d}{dx}(bx+c) \] Using the chain rule, we differentiate \( bx+c \): \[ \frac{d}{dx}(bx+c) = b \] Thus, the first derivative becomes: \[ \frac{dy}{dx} = abe^{bx+c} \] ### Step 3: Differentiate again to find the second derivative Next, we differentiate \( \frac{dy}{dx} \) to find the second derivative \( \frac{d^2y}{dx^2} \): \[ \frac{d^2y}{dx^2} = \frac{d}{dx}(abe^{bx+c}) = ab \cdot e^{bx+c} \cdot \frac{d}{dx}(bx+c) = ab \cdot e^{bx+c} \cdot b \] Thus, the second derivative is: \[ \frac{d^2y}{dx^2} = ab^2 e^{bx+c} \] ### Step 4: Analyze the derivatives Now we have: 1. \( y = ae^{bx+c} \) 2. \( \frac{dy}{dx} = abe^{bx+c} \) 3. \( \frac{d^2y}{dx^2} = ab^2 e^{bx+c} \) ### Step 5: Determine the order of the differential equation The order of a differential equation is defined as the highest derivative present in the equation. In our case, we have the first derivative \( \frac{dy}{dx} \) and the second derivative \( \frac{d^2y}{dx^2} \). Since the highest derivative is the second derivative, the order of the differential equation is: \[ \text{Order} = 2 \] ### Conclusion Thus, the order of the differential equation is 2. ---
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