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The degree of the differential equation ...

The degree of the differential equation `Y_(2) ^(3//2)- Y_(1)^(1//2)-4=0` is :

A

6

B

3

C

2

D

4

Text Solution

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The correct Answer is:
To determine the degree of the differential equation \( Y_2^{3/2} - Y_1^{1/2} - 4 = 0 \), we will follow these steps: ### Step 1: Identify the terms In the given equation: - \( Y_2 \) represents the second derivative of \( y \) with respect to \( x \), which is \( \frac{d^2y}{dx^2} \). - \( Y_1 \) represents the first derivative of \( y \) with respect to \( x \), which is \( \frac{dy}{dx} \). ### Step 2: Rewrite the equation We can rewrite the equation as: \[ Y_2^{3/2} - Y_1^{1/2} = 4 \] This shows the relationship between the derivatives. ### Step 3: Isolate one of the derivatives We can isolate \( Y_1^{1/2} \): \[ Y_2^{3/2} - 4 = Y_1^{1/2} \] ### Step 4: Square both sides To eliminate the square roots, we square both sides: \[ (Y_2^{3/2} - 4)^2 = Y_1 \] Expanding the left-hand side: \[ Y_2^3 - 8Y_2^{3/2} + 16 = Y_1 \] ### Step 5: Identify the highest power of derivatives In this equation, we can see that: - The highest power of \( Y_2 \) (which is \( Y_2 = \frac{d^2y}{dx^2} \)) is \( 3 \). - The highest power of \( Y_1 \) (which is \( Y_1 = \frac{dy}{dx} \)) is \( 1 \). ### Step 6: Determine the degree The degree of a differential equation is defined as the highest power of the highest order derivative when the equation is a polynomial in derivatives. Here, the highest order derivative is \( Y_2 \) and its highest power is \( 3 \). Thus, the degree of the differential equation is: \[ \text{Degree} = 3 \] ### Final Answer The degree of the differential equation \( Y_2^{3/2} - Y_1^{1/2} - 4 = 0 \) is **3**.
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