y(dy)/(dx)sinx=cosx(sinx-(y^2)/2); wher...

`y(dy)/(dx)sinx=cosx(sinx-(y^2)/2);` where at `x=pi/2,`

A

`y^2 = sin x`

B

`y^2 = 2 sin x`

C

`x^2 = sin Y`

D

`x^2 = 2 sin Y`

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The correct Answer is:

A

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