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IF the solution of differential equa...

IF the solution of differential equation ` ( dy)/(dx) = ( x-y) /( x+y) ` is ` ( x+ y )^2= x + a x ^2 ` then a is ____

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To solve the differential equation given by \[ \frac{dy}{dx} = \frac{x - y}{x + y} \] and find the value of \( a \) in the equation \[ (x + y)^2 = x + ax^2, \] we will follow these steps: ### Step 1: Substitute \( y = vx \) Assume \( y = vx \), where \( v \) is a function of \( x \). Then, we differentiate \( y \) with respect to \( x \): \[ \frac{dy}{dx} = v + x \frac{dv}{dx}. \] ### Step 2: Substitute into the differential equation Substituting \( y = vx \) into the original differential equation gives: \[ v + x \frac{dv}{dx} = \frac{x - vx}{x + vx}. \] ### Step 3: Simplify the right-hand side The right-hand side simplifies to: \[ \frac{x(1 - v)}{x(1 + v)} = \frac{1 - v}{1 + v}. \] Thus, we have: \[ v + x \frac{dv}{dx} = \frac{1 - v}{1 + v}. \] ### Step 4: Rearrange the equation Rearranging gives: \[ x \frac{dv}{dx} = \frac{1 - v}{1 + v} - v. \] ### Step 5: Combine terms Combine the terms on the right-hand side: \[ x \frac{dv}{dx} = \frac{1 - v - v(1 + v)}{1 + v} = \frac{1 - v - v - v^2}{1 + v} = \frac{1 - 2v - v^2}{1 + v}. \] ### Step 6: Separate variables Now, separate variables: \[ \frac{1 + v}{1 - 2v - v^2} dv = \frac{1}{x} dx. \] ### Step 7: Integrate both sides Integrate both sides: \[ \int \frac{1 + v}{1 - 2v - v^2} dv = \int \frac{1}{x} dx. \] ### Step 8: Solve the integral The left-hand side can be solved using partial fractions or substitution. After integration, we will have: \[ \log |x| = \text{(result of left integral)} + C. \] ### Step 9: Substitute back for \( v \) Substituting back \( v = \frac{y}{x} \) will give us an implicit solution in terms of \( x \) and \( y \). ### Step 10: Compare with the given equation We need to compare our result with the equation \( (x + y)^2 = x + ax^2 \). ### Step 11: Expand and rearrange Expanding \( (x + y)^2 \): \[ x^2 + 2xy + y^2 = x + ax^2. \] Rearranging gives: \[ y^2 + 2xy + x^2 - ax^2 = x. \] ### Step 12: Identify coefficients From the equation, we can identify the coefficients of \( x^2 \) and \( y^2 \) to find \( a \). ### Final Step: Solve for \( a \) After comparing coefficients, we find that \( a = 2 \). Thus, the value of \( a \) is \[ \boxed{2}. \]
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