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The solution of the differential eq...

The solution of the differential equation ` x(dy)/(dx) + 2y = x^2 (X ne 0)` with ` y(1) =1,` is :

A

`y= (4)/(5)x^3+(1)/(5x^2)`

B

`y= (x^3)/(5)+ (1)/(5x ^2)`

C

` y=( x^2 )/(4) +(3)/(4x ^2)`

D

`y=(3)/(4)x^2 +(1)/(4x^2)`

Text Solution

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The correct Answer is:
To solve the differential equation \( x \frac{dy}{dx} + 2y = x^2 \) with the initial condition \( y(1) = 1 \), we will follow these steps: ### Step 1: Rewrite the equation We start with the given equation: \[ x \frac{dy}{dx} + 2y = x^2 \] We can divide the entire equation by \( x \) (since \( x \neq 0 \)): \[ \frac{dy}{dx} + \frac{2}{x} y = x \] ### Step 2: Identify \( p \) and \( q \) Now, we can identify \( p \) and \( q \) from the standard form \( \frac{dy}{dx} + p y = q \): - \( p = \frac{2}{x} \) - \( q = x \) ### Step 3: Find the integrating factor The integrating factor \( \mu(x) \) is given by: \[ \mu(x) = e^{\int p \, dx} = e^{\int \frac{2}{x} \, dx} \] Calculating the integral: \[ \int \frac{2}{x} \, dx = 2 \ln |x| = \ln |x|^2 \] Thus, the integrating factor becomes: \[ \mu(x) = e^{\ln |x|^2} = x^2 \] ### Step 4: Multiply through by the integrating factor Now, we multiply the entire differential equation by the integrating factor \( x^2 \): \[ x^2 \frac{dy}{dx} + 2xy = x^3 \] ### Step 5: Rewrite the left side as a derivative The left side can be rewritten as: \[ \frac{d}{dx}(y \cdot x^2) = x^3 \] ### Step 6: Integrate both sides Integrating both sides with respect to \( x \): \[ \int \frac{d}{dx}(y \cdot x^2) \, dx = \int x^3 \, dx \] This gives: \[ y \cdot x^2 = \frac{x^4}{4} + C \] ### Step 7: Solve for \( y \) Now, we can solve for \( y \): \[ y = \frac{x^4}{4x^2} + \frac{C}{x^2} = \frac{x^2}{4} + \frac{C}{x^2} \] ### Step 8: Apply the initial condition We use the initial condition \( y(1) = 1 \): \[ 1 = \frac{1^2}{4} + \frac{C}{1^2} \] This simplifies to: \[ 1 = \frac{1}{4} + C \implies C = 1 - \frac{1}{4} = \frac{3}{4} \] ### Step 9: Substitute \( C \) back into the equation Now substituting \( C \) back into the equation for \( y \): \[ y = \frac{x^2}{4} + \frac{3/4}{x^2} \] ### Final Solution Thus, the final solution to the differential equation is: \[ y = \frac{x^2}{4} + \frac{3}{4x^2} \]
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