[" 2"64" mis a the integer "11,000" that: "],[(sqrt(3)+i)^(n)+(sqrt(3)-1)^(n)=2^(n-1)cos(n pi)/(6)]

If n is a positive integer, then (sqrt(3)+1)^(2n)-(sqrt(3)-1)^(2n) is

If n is a positive integer, then: (sqrt(3)+1)^(2n)-(sqrt(3)-1)^(2n) is:

If n is a positive integer , then (sqrt(3)+1)^(2n)-(sqrt(3)-1)^(2n) is -

Prove that (a)(1+i)^(n)+(1-i)^(n)=2^((n+2)/(2))*cos((n pi)/(4)) where n is a positive integer. (b) (1+i sqrt(3))^(n)+(1-i sqrt(3)^(n)=2^(n+1)cos((n pi)/(3)), where n is a positive integer

Assertion (A) : (sqrt3+i)^6+(sqrt3-i)^6=-128 Reason (R) : If n is a positive integer then (sqrt3+i)^n+(sqrt3-i)^n=2^(n+1)cos(npi)/(6)

n is any integer then arg(((sqrt(3)+i)^(4n+1))/((1-sqrt(3)i)^(4n)))=....

If n is a possible integer, then (sqrt3+1)^(2n)-(sqrt3-1)^(2n) is

If n is a positive integer prove that (1+i)^(2n)+(1-i)^(2n)=2^(n+1)cos((n pi)/(2))