Home
Class 12
CHEMISTRY
The bond dissociation energy of N(2)^(+...

The bond dissociation energy of `N_(2)^(+)` is less than that of `N_(2)` . Show why this is the case.

Text Solution

Verified by Experts

E.C. of `N_(2): (sigma_(1s))^(2) (sigma_(1s)^(**))^(2) (sigma_(2s))^(2) (sigma_(2s)^(**))^(2) (pi 2px)^(2)(pi 2py)^(2)(sigma 2p_(z))^(1)`
E.C. of `N_(2)^(+) : (sigma_(1s))^(2) (sigma_(1s)^(**))^(2) (sigma_(2s))^(2) (sigma_(2s)^(**))^(2) (pi 2p_(x))^(2)(pi 2p_(y))^(2)(sigma 2p_(z))^(1)`
Bond order of `N_(2)=(10-4)/(2)=3` , Bond order of `N_(2)^(+) =(9-4)/(2)=2.5`
Bond energy `prop` bond order , Bond energy of `N_(2)^(+) lt N_(2) therefore` Bond dissociation energy of `N_(2)^(+)` is less than `N_(2)`
Promotional Banner

Similar Questions

Explore conceptually related problems

Bond dissociation energy of F_(2) is less that of Cl_(2) give reason.

Given reasons in two or three sentences only for (i) Bond dissociation energy of F_(2) is less than that of CI_(2) . (ii) Sulphur dioxide is a more powerful reducing agent in the alkaline medium than in acidic medium.

Assertion: Bond dissociation energy of F_(2) molecule is less than that of Cl_(2) molecule. Reason: Due to inter-electronic repulsion between F atom, F-F bond length in F_(2) molecule is higher than Cl-Cl bond lengthh in Cl_(2) molecule.

Correct order of dissociation energy of N_(2) and N_(2)^(+) is:

Bond dissociation enthalpy of F-F bond is less than that of Cl-Cl bond. Explain.