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Select the correct statement....

Select the correct statement.

A

`BF_(3) and NH_(3)` have same dipole moment

B

Dipole moment of `NH_(3)` is smaller than that of `BF_(3)`

C

`BF_(3)` molecule has a planar structure, while the `NH_(3)` molecule is tetrahedral

D

The nitrogen atom has unshared pair of electrons, while the boron atom has a free (vacant) valence orbital.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question of selecting the correct statement regarding BF3 and NH3, we will analyze the properties of both molecules step by step. ### Step 1: Analyze BF3 1. **Valence Electrons**: Boron (B) has 3 valence electrons and each Fluorine (F) has 7 valence electrons. 2. **Bonding**: Boron forms three bonds with three Fluorine atoms using its three valence electrons. 3. **Lone Pairs**: There are no lone pairs on Boron in BF3. 4. **Steric Number**: The steric number is 3 (3 bond pairs, 0 lone pairs). 5. **Hybridization**: The hybridization of BF3 is sp². 6. **Molecular Geometry**: The geometry is trigonal planar. 7. **Dipole Moment**: Due to the symmetry of the molecule, the dipole moments of the B-F bonds cancel out, resulting in a net dipole moment of zero. ### Step 2: Analyze NH3 1. **Valence Electrons**: Nitrogen (N) has 5 valence electrons and each Hydrogen (H) has 1 valence electron. 2. **Bonding**: Nitrogen forms three bonds with three Hydrogen atoms using three of its valence electrons. 3. **Lone Pairs**: There is one lone pair on Nitrogen. 4. **Steric Number**: The steric number is 4 (3 bond pairs, 1 lone pair). 5. **Hybridization**: The hybridization of NH3 is sp³. 6. **Molecular Geometry**: The geometry is tetrahedral, but the shape is trigonal pyramidal due to the lone pair. 7. **Dipole Moment**: The dipole moment is directed from the Hydrogen atoms towards the Nitrogen atom due to the electronegativity difference, resulting in a net dipole moment of approximately 1.46 D. ### Step 3: Evaluate the Statements 1. **Statement 1**: "BF3 and NH3 have the same dipole moment." - **Incorrect** (BF3 has a dipole moment of 0, NH3 has a dipole moment of 1.46 D). 2. **Statement 2**: "The dipole moment of NH3 is smaller than that of BF3." - **Incorrect** (NH3 has a dipole moment of 1.46 D, while BF3 has 0 D). 3. **Statement 3**: "BF3 molecule has a planar structure." - **Correct** (BF3 is trigonal planar). 4. **Statement 4**: "NH3 molecule is tetrahedral." - **Incorrect** (NH3 is trigonal pyramidal due to the lone pair). 5. **Statement 5**: "The nitrogen atom has an unshared pair of electrons, while the boron atom has a free valence orbital." - **Correct** (Nitrogen has a lone pair, and Boron has a free valence orbital). ### Conclusion The correct statements are: - "BF3 molecule has a planar structure." - "The nitrogen atom has an unshared pair of electrons, while the boron atom has a free valence orbital." ### Final Answer The correct statement is: "BF3 molecule has a planar structure."

To solve the question of selecting the correct statement regarding BF3 and NH3, we will analyze the properties of both molecules step by step. ### Step 1: Analyze BF3 1. **Valence Electrons**: Boron (B) has 3 valence electrons and each Fluorine (F) has 7 valence electrons. 2. **Bonding**: Boron forms three bonds with three Fluorine atoms using its three valence electrons. 3. **Lone Pairs**: There are no lone pairs on Boron in BF3. 4. **Steric Number**: The steric number is 3 (3 bond pairs, 0 lone pairs). 5. **Hybridization**: The hybridization of BF3 is sp². ...
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