In which of the following compound, centre atom forms six or more than six hybrid orbitals ?

Options

A. `PCl_(5)`
B. `CO_(3)^(2-)`
C. `SO_(3)`
D. `XeF_(6)`

Explanation

To determine in which of the following compounds the central atom forms six or more than six hybrid orbitals, we will analyze each compound step by step.

### Step 1: Analyze PCl5
- **Valence Electrons**: Phosphorus (P) has 5 valence electrons, and each Chlorine (Cl) has 7 valence electrons. In PCl5, there are 5 Chlorine atoms.
- **Bonding**: Phosphorus forms 5 single bonds with 5 Chlorine atoms.
- **Lone Pairs**: There are no lone pairs on the phosphorus atom.
- **Steric Number Calculation**: Steric number = Number of bond pairs + Number of lone pairs = 5 + 0 = 5.
- **Hybridization**: The hybridization is sp³d (5 hybrid orbitals).

### Step 2: Analyze CO3^2-
- **Valence Electrons**: Carbon (C) has 4 valence electrons, and each Oxygen (O) has 6 valence electrons. For CO3^2-, we have 3 Oxygens and 2 extra electrons due to the 2- charge.
- **Bonding**: Carbon forms 1 double bond with one Oxygen and 2 single bonds with the other two Oxygens.
- **Lone Pairs**: There are no lone pairs on the carbon atom.
- **Steric Number Calculation**: Steric number = Number of bond pairs + Number of lone pairs = 3 + 0 = 3.
- **Hybridization**: The hybridization is sp² (3 hybrid orbitals).

### Step 3: Analyze SF6
- **Valence Electrons**: Sulfur (S) has 6 valence electrons, and each Fluorine (F) has 7 valence electrons. In SF6, there are 6 Fluorine atoms.
- **Bonding**: Sulfur forms 6 single bonds with 6 Fluorine atoms.
- **Lone Pairs**: There are no lone pairs on the sulfur atom.
- **Steric Number Calculation**: Steric number = Number of bond pairs + Number of lone pairs = 6 + 0 = 6.
- **Hybridization**: The hybridization is sp³d² (6 hybrid orbitals).

### Step 4: Analyze XeF6
- **Valence Electrons**: Xenon (Xe) has 8 valence electrons, and each Fluorine (F) has 7 valence electrons. In XeF6, there are 6 Fluorine atoms.
- **Bonding**: Xenon forms 6 single bonds with 6 Fluorine atoms.
- **Lone Pairs**: There are 2 lone pairs on the xenon atom.
- **Steric Number Calculation**: Steric number = Number of bond pairs + Number of lone pairs = 6 + 2 = 8.
- **Hybridization**: The hybridization is sp³d³ (8 hybrid orbitals).

### Conclusion
Among the compounds analyzed, the central atom forms six or more than six hybrid orbitals in:
- **SF6** (6 hybrid orbitals)
- **XeF6** (8 hybrid orbitals)

Thus, the correct answer is **XeF6**.