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Which of the following molecule have sam...

Which of the following molecule have same structure and shape ?

A

`IF_(7)`

B

`[AlF_(6)]^(3-)`

C

`BrF_(5)`

D

`XeOF_(4)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given molecules have the same structure and shape, we need to analyze the molecular geometry and hybridization of each molecule. Here’s a step-by-step breakdown of the analysis: ### Step 1: Analyze IF7 1. **Valence Electrons**: Iodine (I) has 7 valence electrons, and each Fluorine (F) has 7 valence electrons. Since there are 7 Fluorine atoms, we have a total of 7 bond pairs. 2. **Lone Pairs**: There are no lone pairs on Iodine. 3. **Steric Number**: The steric number is 7 (7 bond pairs + 0 lone pairs). 4. **Hybridization**: The hybridization is sp³d³. 5. **Shape and Structure**: The shape is pentagonal bipyramidal, and the structure is also pentagonal bipyramidal. ### Step 2: Analyze AlF6³⁻ 1. **Valence Electrons**: Aluminum (Al) has 3 valence electrons, and with a -3 charge, it effectively has 6 valence electrons from Fluorine. This results in 6 bond pairs. 2. **Lone Pairs**: There are no lone pairs on Aluminum. 3. **Steric Number**: The steric number is 6 (6 bond pairs + 0 lone pairs). 4. **Hybridization**: The hybridization is sp³d². 5. **Shape and Structure**: The shape is octahedral, and the structure is also octahedral. ### Step 3: Analyze BrF5 1. **Valence Electrons**: Bromine (Br) has 7 valence electrons, and with 5 Fluorine atoms, it forms 5 bond pairs. 2. **Lone Pairs**: There is 1 lone pair on Bromine. 3. **Steric Number**: The steric number is 6 (5 bond pairs + 1 lone pair). 4. **Hybridization**: The hybridization is sp³d². 5. **Shape and Structure**: The shape is square pyramidal, while the structure is octahedral. They are different. ### Step 4: Analyze XeF4 1. **Valence Electrons**: Xenon (Xe) has 8 valence electrons, and it forms 4 bond pairs with Fluorine. 2. **Lone Pairs**: There are 2 lone pairs on Xenon. 3. **Steric Number**: The steric number is 6 (4 bond pairs + 2 lone pairs). 4. **Hybridization**: The hybridization is sp³d². 5. **Shape and Structure**: The shape is square planar, while the structure is octahedral. They are different. ### Conclusion From the analysis: - **IF7** has the same shape and structure (pentagonal bipyramidal). - **AlF6³⁻** also has the same shape and structure (octahedral). - **BrF5** and **XeF4** have different shapes and structures. ### Final Answer The molecules that have the same structure and shape are **IF7** and **AlF6³⁻**.

To determine which of the given molecules have the same structure and shape, we need to analyze the molecular geometry and hybridization of each molecule. Here’s a step-by-step breakdown of the analysis: ### Step 1: Analyze IF7 1. **Valence Electrons**: Iodine (I) has 7 valence electrons, and each Fluorine (F) has 7 valence electrons. Since there are 7 Fluorine atoms, we have a total of 7 bond pairs. 2. **Lone Pairs**: There are no lone pairs on Iodine. 3. **Steric Number**: The steric number is 7 (7 bond pairs + 0 lone pairs). 4. **Hybridization**: The hybridization is sp³d³. 5. **Shape and Structure**: The shape is pentagonal bipyramidal, and the structure is also pentagonal bipyramidal. ...
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