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In which reaction, the hybridisation on ...

In which reaction, the hybridisation on the central atom changes from `sp^(2)` to `sp^(3)`.

A

`NH_(3)+H^(+) to NH_(4)^(+)`

B

`BF_(3)+F^(-) to BF_(4)^(-)`

C

`H_(2)O+H^(+) to H_(3)O^(+)`

D

`C_(2)H_(2)+2H_(2) to C_(2)H_(6)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine in which reaction the hybridization on the central atom changes from `sp²` to `sp³`, we need to analyze the reactions involving central atoms and their hybridization states. ### Step-by-Step Solution: 1. **Identify the Central Atom and its Initial Hybridization**: - We start with a molecule that has a central atom with `sp²` hybridization. A common example is boron in boron trifluoride (BF₃), which has a steric number of 3 (three bond pairs and no lone pairs). 2. **Reaction Involving the Central Atom**: - Consider the reaction of BF₃ with a fluoride ion (F⁻) to form BF₄⁻. In this reaction, BF₃ (with boron at `sp²` hybridization) reacts with F⁻. 3. **Determine the New Hybridization After Reaction**: - In BF₄⁻, boron now has four bond pairs (one from each fluorine atom) and no lone pairs. The steric number is now 4, which corresponds to `sp³` hybridization. 4. **Conclusion**: - Thus, in the reaction of BF₃ with F⁻ to form BF₄⁻, the hybridization of boron changes from `sp²` to `sp³`. ### Final Answer: The reaction in which the hybridization on the central atom changes from `sp²` to `sp³` is: **BF₃ + F⁻ → BF₄⁻** ---
To determine in which reaction the hybridization on the central atom changes from `sp²` to `sp³`, we need to analyze the reactions involving central atoms and their hybridization states. ### Step-by-Step Solution: 1. **Identify the Central Atom and its Initial Hybridization**: - We start with a molecule that has a central atom with `sp²` hybridization. A common example is boron in boron trifluoride (BF₃), which has a steric number of 3 (three bond pairs and no lone pairs). 2. **Reaction Involving the Central Atom**: ...
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