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The hybridization of atomic orbitals of ...

The hybridization of atomic orbitals of nitrogen is `NO_(2)^(+), NO_(3)^(-)`, and `NH_(4)^(+)` respectively are

A

`sp, sp^(2),sp^(3)`

B

`sp^(2), sp, sp^(3)`

C

`sp, sp^(3), sp^(2)`

D

`sp^(2), sp^(3), sp`

Text Solution

Verified by Experts

The correct Answer is:
B
The formula to find the hybridization of central atom is `Z=(1)/(2)` [Number of valence electrons on central atom + No. of monovalent atom attached to it + negative charge if any – positive charge if any]
For `NO_(3)^(-), Z=(1)/(2)[5+0+1-0]=3`

For `NO_(2)^(+), Z=(1)/(2)[5+0+0-1]=2" " O=overset(+)N=O to sp`
For ` NH_(4)^(+), Z=(1)/(2)[5+4+0-1]=4`
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