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Molecule AB has a bond length of 1.617Å ...

Molecule AB has a bond length of `1.617Å` and a dipole moment of 0.38 D. The fractional charge on each atom (absolute magnitude) is :
`(e_(0)=4.802xx10^(-10)"esu")`

A

0

B

0.05

C

0.5

D

`1.0`

Text Solution

Verified by Experts

The correct Answer is:
B
Dipole moment = |charge| `xx` bond length `0.38xx10^(-8)` esu cm = | charge | `xx 1.6xx10^(-8)cm`
Charge `=(0.38)/(1.6)xx10^(-10)` esu
Fraction of charge present on each atom `=(0.23xx10^(-10))/(4.8xx10^(-10))=0.05`
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