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The correct statement among the followin...

The correct statement among the following is:

A

`(SiH_(3))_(3)N` is planar and less basic than `(CH_(3))_(3)N`

B

`(SiH_(3))_(3)N` is planar and more basic than `(CH_(3))_(3)N`

C

`(SiH_(3))_(3)N` is pyramidal and less basic than `(CH_(3))_(3)N`

D

`(SiH_(3))_(3)N` is pyramidal and more basic than `(CH_(3))_(3)N`

Text Solution

Verified by Experts

The correct Answer is:
A
Due to formation of `p pi-d pi` back bonding. `N(SiH_(3))` is `Sp^(2)` hybridized. Hence it is planar and less basic than `N(CH_(3))_(3)`.
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