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The dipole momnet of KCI is 3.336 xx 10^...

The dipole momnet of `KCI` is `3.336 xx 10^(-29) Cm` which indicates that it is a highly polar molecules. The inter atomic distance between `K^(o+)` and `CI^(Theta)` in this molecules is `2.6 xx10^(-10)` m Calculate the dipole moment of `KCI` molecule if there were opposite charges of one fundamental unit located at each nucleus Calculate the ionic character percentage of `KCI` .

Text Solution

Verified by Experts

The correct Answer is:
`4.16xx10^(-29), 80.2%`
Dipole moment is calculated theoretically as `mu=q.d`
Here, `q=1.6xx10^(-19)C and d=2.6xx10^(-10)m, mu_("Theo")=1.6xx10^(-19)xx2.6xx10^(-10)=4.16xx10^(-29)cm`
% ionic character `=(mu_("obs"))/(mu_("Theo"))xx100=(3.336xx10^(-29))/(4.16xx10^(-29))xx100=80.2%`
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