Home
Class 12
CHEMISTRY
Nodal planes of pi-bonds in CH(2)=C=C=CH...

Nodal planes of `pi`-bonds in `CH_(2)=C=C=CH_(2)` are located in,

A

the molecular plane

B

a plane parallel to the molecular plane

C

a plane perpendicular to the molecular plane.

D

a plane perpendicular to the molecular plane which contains the carbon-carbon `-sigma` bond

Text Solution

Verified by Experts

The correct Answer is:
A, C


Pi bond is formed by the p-orbitals whose lobes have minima in the plane of molecule, hence molecular plane and a plane perpendicular to the molecular plane is the nodal plane of pi-bond.
Promotional Banner

Similar Questions

Explore conceptually related problems

CH_(2)=CH-C-=C-CH_(2)OH

Total number of pi bonds in CH_(3)-CH=CH-CH_(2)-C-=CH is ________.

How many sigma bonds and pi bonds are present in CH_(2)=C=CH_(2) ?

Statement-1 : H_(2)C=C=C=CH_(2) molecule is planar. Statement-2 : Nodal planes of all pi- bonds are lying in the same plane.

Number of bonds in given compound is: CH_(2)=C=CH-C=CH

The number of sigma bonds in CH_(2)=CH - CH = CH - C -= CH is _________.

Statement-I: All C-C bod lengths are equal in CH_(2)=CH-CH=CH_(2) Statement-II: There is resonance between two pi bonds.