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The sum of the number of lone pair of el...

The sum of the number of lone pair of electrons on each central atom in the following species is
`[TeBr_(6)]^(2-), [BrF_(2)]^(2+), SNF_(3), and [XeF_(3)]^(-)`
(Atomic number : N = 7, F = 9, S = 16, Br = 35, Te = 52, Xe = 54)

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To find the sum of the number of lone pairs of electrons on each central atom in the given species, we will analyze each species one by one. ### Step 1: Analyze [TeBr₆]²⁻ 1. **Valence Electrons Calculation**: - Tellurium (Te) has 6 valence electrons. - The charge of -2 means we add 2 more electrons. - Total valence electrons for Te = 6 + 2 = 8. 2. **Bonding with Bromine (Br)**: - Each Bromine contributes 1 electron for bonding. - With 6 Br atoms, we use 6 electrons for 6 bond pairs. 3. **Lone Pairs Calculation**: - Total electrons = 8 (from Te) - 6 (used in bonding) = 2 electrons left. - These 2 electrons form 1 lone pair. **Lone pairs on Te = 1** ### Step 2: Analyze [BrF₂]²⁺ 1. **Valence Electrons Calculation**: - Bromine (Br) has 7 valence electrons. - The charge of +2 means we subtract 2 electrons. - Total valence electrons for Br = 7 - 2 = 5. 2. **Bonding with Fluorine (F)**: - Each Fluorine contributes 1 electron for bonding. - With 2 F atoms, we use 2 electrons for 2 bond pairs. 3. **Lone Pairs Calculation**: - Total electrons = 5 (from Br) - 2 (used in bonding) = 3 electrons left. - These 3 electrons form 1 lone pair (2 electrons) and 1 single electron (which does not form a lone pair). **Lone pairs on Br = 1** ### Step 3: Analyze SNF₃ 1. **Valence Electrons Calculation**: - Sulfur (S) has 6 valence electrons. - Nitrogen (N) has 5 valence electrons. - Each Fluorine (F) has 1 valence electron. - Total = 6 (S) + 5 (N) + 3 (F) = 14 valence electrons. 2. **Bonding**: - N forms 3 bonds with 3 F atoms using 3 electrons. - S forms a double bond with N using 2 electrons. 3. **Lone Pairs Calculation**: - Total electrons = 14 - (3 + 2) = 9 electrons left. - N has no lone pairs, and S has 4 electrons left, which forms 2 lone pairs. **Lone pairs on S = 2** ### Step 4: Analyze [XeF₃]⁻ 1. **Valence Electrons Calculation**: - Xenon (Xe) has 8 valence electrons. - The charge of -1 means we add 1 more electron. - Total valence electrons for Xe = 8 + 1 = 9. 2. **Bonding with Fluorine (F)**: - Each Fluorine contributes 1 electron for bonding. - With 3 F atoms, we use 3 electrons for 3 bond pairs. 3. **Lone Pairs Calculation**: - Total electrons = 9 (from Xe) - 3 (used in bonding) = 6 electrons left. - These 6 electrons form 3 lone pairs. **Lone pairs on Xe = 3** ### Final Calculation: Now, we sum the lone pairs from each central atom: - Lone pairs on Te = 1 - Lone pairs on Br = 1 - Lone pairs on S = 2 - Lone pairs on Xe = 3 **Total lone pairs = 1 + 1 + 2 + 3 = 7** ### Answer: The sum of the number of lone pairs of electrons on each central atom in the species is **7**.

To find the sum of the number of lone pairs of electrons on each central atom in the given species, we will analyze each species one by one. ### Step 1: Analyze [TeBr₆]²⁻ 1. **Valence Electrons Calculation**: - Tellurium (Te) has 6 valence electrons. - The charge of -2 means we add 2 more electrons. - Total valence electrons for Te = 6 + 2 = 8. ...
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