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The molecular velocities of two gases at...

The molecular velocities of two gases at same temperature are `u_(1)` and `u_(2)`, their masses are `m_(1)` and `m_(2)` respectively, which of the following expression is correct ?

A

`(m_(1))/(u_(1)^(2)) = (m_(2))/(u_(2)^(2))`

B

`m_(1) u_(1) = m_(2) u_(2)`

C

`(m_(1))/(u_(1)) = (m_(2))/(u_(2))`

D

`m_(1) u_(1)^(2) = m_(2) u_(2)^(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`C prop (T)/(sqrtM) rArr u_(1) prop (T)/(sqrt(m_(1))) and u_(2) prop (T)/(sqrt(m_(2))) rArr u_(1) sqrt(m_(1)) = u_(2) sqrt(m_(2)) rArr m_(1) u_(1)^(2) = m_(2) u_(2)^(2)`
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