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The average kinetic energy of an ideal g...

The average kinetic energy of an ideal gas per molecule in SI units at `25^(@)C` will be

A

`6.17 xx 10^(-21) kJ`

B

`6.17 xx 10^(-21)J`

C

`6.17 xx 10^(-20)J`

D

`6.17 xx 10^(-20) kJ`

Text Solution

Verified by Experts

The correct Answer is:
B
K.Eavg per molecule `=(3)/(2) KT = (3)/(2) xx 1.38 xx 10^(-23) xx 298 ~ 617 xx 10^(-21)J`
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