Consider the reaction `2Al (g) + 3Cl_(2) (g) rArr 2Al Cl_(3) (g)`. The approximate volume of chlorine that would react with 324 g of aluminium at STP is :

Options

A. 112 L
B. 134 L
C. 260 L
D. 403 L

Answer

D

Explanation

324 g Al `-= (324)/(27) = 12mol Al -= (12 xx 3)/(2) mol Cl_(2) = 18mol Cl_(2) = -= 18 xx 22.4` It of `Cl_(2)`ats.T.P.= 403.2 lt