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The rate of effusion of two gases 'a' an...

The rate of effusion of two gases `'a'` and `'b'` under identical conditions of temperature and pressure are in the ratio of `2:1` What is the ratio of `rms` velocity of their molecules if `T_(a)` and `T_(b)` are in the ratio of `2:1`?

A

`2 : 1`

B

`sqrt2 : 1`

C

`2sqrt2 : 1`

D

`1 : sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
C
`(r_(A))/(r_(B)) = (2)/(1) = sqrt((M_(B))/(M_(A))) , (C_(rm s)A)/(C_(rm s)B) = sqrt((T_(A))/(M_(A)).(M_(B))/(T_(B))) = sqrt((2)/(1)) xx 2 = (2 sqrt2)/(1)` [Rate `prop C_(rm s)`]
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