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Under same conditions of temperature and...

Under same conditions of temperature and pressure, a hydrocarbon of molecular formula `C_(n)H_(2n-2)` was found to diffuse `3sqrt3` times slower than hydrogen. Find the value of n.

A

n = 2

B

n = 4

C

n = 3

D

n = 1

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use Graham's law of diffusion and the information provided about the hydrocarbon. ### Step 1: Understand the relationship given in the problem We know that the hydrocarbon with the formula \( C_nH_{2n-2} \) diffuses \( 3\sqrt{3} \) times slower than hydrogen. According to Graham's law of diffusion, the rate of diffusion is inversely proportional to the square root of the molecular mass. ### Step 2: Set up the equation using Graham's law Let \( R_{H_2} \) be the rate of diffusion of hydrogen and \( R_{hydrocarbon} \) be the rate of diffusion of the hydrocarbon. From the problem, we have: \[ \frac{R_{H_2}}{R_{hydrocarbon}} = 3\sqrt{3} \] ### Step 3: Relate the rates to molecular masses According to Graham's law: \[ \frac{R_{H_2}}{R_{hydrocarbon}} = \sqrt{\frac{M_{hydrocarbon}}{M_{H_2}}} \] Where \( M_{H_2} \) is the molecular mass of hydrogen, which is 2 g/mol. Therefore, we can set up the equation: \[ 3\sqrt{3} = \sqrt{\frac{M_{hydrocarbon}}{2}} \] ### Step 4: Square both sides to eliminate the square root Squaring both sides gives: \[ (3\sqrt{3})^2 = \frac{M_{hydrocarbon}}{2} \] \[ 27 = \frac{M_{hydrocarbon}}{2} \] ### Step 5: Solve for the molecular mass of the hydrocarbon Multiplying both sides by 2: \[ M_{hydrocarbon} = 54 \text{ g/mol} \] ### Step 6: Write the expression for the molecular mass of the hydrocarbon The molecular mass of the hydrocarbon \( C_nH_{2n-2} \) can be calculated as follows: \[ M_{hydrocarbon} = 12n + (2n - 2) \] This simplifies to: \[ M_{hydrocarbon} = 12n + 2n - 2 = 14n - 2 \] ### Step 7: Set up the equation with the known molecular mass Now we set the expression for the molecular mass equal to the value we found: \[ 14n - 2 = 54 \] ### Step 8: Solve for \( n \) Adding 2 to both sides: \[ 14n = 56 \] Dividing both sides by 14: \[ n = 4 \] ### Final Answer The value of \( n \) is \( 4 \). ---

To solve the problem step by step, we will use Graham's law of diffusion and the information provided about the hydrocarbon. ### Step 1: Understand the relationship given in the problem We know that the hydrocarbon with the formula \( C_nH_{2n-2} \) diffuses \( 3\sqrt{3} \) times slower than hydrogen. According to Graham's law of diffusion, the rate of diffusion is inversely proportional to the square root of the molecular mass. ### Step 2: Set up the equation using Graham's law Let \( R_{H_2} \) be the rate of diffusion of hydrogen and \( R_{hydrocarbon} \) be the rate of diffusion of the hydrocarbon. From the problem, we have: \[ ...
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