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Density of dry air ( only N(2) and O(2))...

Density of dry air `(` only `N_(2)` and `O_(2))` is `1.24g` `litre^(-1)` at `760 m m` and `300 K`. Find the partial pressure of `N_(2)` gas in aire. ( Take `R=(1)/(12)` litre litre atm`//`mol K, mol. Wt. of `N_(2) =28)`

A

0.25

B

0.365

C

0.5

D

0.75

Text Solution

Verified by Experts

The correct Answer is:
B
`P_("Total") = (dRT)/(M_(o)) rArr M_(o) = (dRT)/(P_(T)) = (1.24 xx 0.0821 xx 300)/(760//760) rArr M_(0) = 30.54`
`M_(0)` 'here is the molar mass of air
`M_(o) = X_(N_(2)) M_(N_(2)) + X_(O_(2)) M_(O_(2)) = X_(N_(2)) M_(N_(2)) + (1-X_(N_(2))) M_(O_(2))`
`30.54 = X_(N_(2)) (M_(N_(2)) - M_(O_(2))) + M_(O_(2)) = X_(N_(2)) (28-32) + 32`
`30.54 - 32 = -4X_(N_(2))`
`0.365 = X_(N_(2))`
`P_(N_(2)) = X_(N_(2)) P_(T) = 0.365 xx 1 atm = 0.365 atm`
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