Home
Class 12
CHEMISTRY
A gaseous mixture containing He, CH(4) a...

A gaseous mixture containing He, `CH_(4)` and `SO_(2)` in `1:2:3` mole ratio, calculate the molar ratio of gases effusing out initially.

A

`2 : 2 : 3`

B

`6 : 6 : 1`

C

`sqrt2 : sqrt2 : 3`

D

`4 : 4`

Text Solution

Verified by Experts

The correct Answer is:
D

`(n'_(He))/(n'_(CH_(4))) = (1)/(2) sqrt((16)/(4)) = (1)/(1), (n'_(He))/(n'_(SO_(2))) = (1)/(3) sqrt((64)/(4)) = (4)/(3), n'_(He) : n'_(CH_(4)) : n'_(SO_(2)) = 4 : 4 : 3`
Promotional Banner

Similar Questions

Explore conceptually related problems

A gaseous mixture contains equal mass of CH_(4) and SO_(2) gas. The mole fraction of SO_(2) in the mixture is

A mixture of gases contains H_(2) and O_(2) gases in the ratio of 1:4 (w//w) . What is the molar ratio of the two gases in the mixture?

A gaseous mixture contains SO_(3)(g) and CH_(4)(g) in 12.5 : 1 ratio by mass. Calculate X where X = Ratio of total number of atoms present in SO_(3)(g) to total number of atoms presents in CH_(4)(g) in the mixure.